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X^2+49X+100=0
a = 1; b = 49; c = +100;
Δ = b2-4ac
Δ = 492-4·1·100
Δ = 2001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-\sqrt{2001}}{2*1}=\frac{-49-\sqrt{2001}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+\sqrt{2001}}{2*1}=\frac{-49+\sqrt{2001}}{2} $
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